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Raspberry Pi Stack Exchange is a question and answer site for users and developers of hardware and software for Raspberry Pi. It only takes a minute to sign up. What other things should I be concerned with, or would I need to verify, before trying this out reasonably safely?
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There are many available but be sure to check the amperage output. Typically the microUSB socket gives you the polyfuse protection and it's less likely that the power polarity will be wrong. Sign up to join this community.How to convert 12v Dc or 9v Dc to 5v Dc using IC L7805
The best answers are voted up and rise to the top. Home Questions Tags Users Unanswered. Asked 9 months ago. Active 5 months ago. Viewed times. I have an Eleksmaker laser cutter which has a board with a 12V output see top of image. I would like to power my RaspberryPi using this 12V output. LBogaardt LBogaardt 2 2 bronze badges. Active Oldest Votes. Doug Wyman Doug Wyman 66 3 3 bronze badges. I often power a Pi via the 5V and ground pins on the expansion header. Search this site for the advantages and disadvantages.
Need to reduce voltage using as few and as small components as possible
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Community and Moderator guidelines for escalating issues via new response…. Feedback on Q2 Community Roadmap.I'm in software, and I'm an idiot. When doing hardware design, I'm therefore limited to very simple circuits, or following premade schematics. This time, though, I can't seem to Google up everything that I'm looking for.
I also have a voltage source which will be either 12v as shown or 5v depending on the chosen external connection. So, to make sure the 5v device isn't destroyed by a 12v source, I'm trying to limit the voltage to the 5v device.
Hopefully that makes sense. Hopefully how I've chosen to limit the voltage also makes sense: current will flow to both devices until it exceeds 5v, at which point the zener will break down and current will instead flow to the 12v device and ground. That's my theory, anyway. So: 1. Will current still flow to the 12v device if the zener breaks down?
What is a reasonable value for that resistor? What else did I miss? Thanks for the help! Your image is broken. To drop your voltage from 12 to 5, you'll need a 7V zener. Hmm, can't say I've ever seen one, but you could use two. Just make sure that your current isn't too high, otherwise your zeners will blow. The second most dangerous thing in the world is a software guy with a soldering iron.
The most dangerous thing in the world is a manager who thinks he can code. I got nothin'. GIF This should work to drop the voltage from 12 to 5. DC-DC Converters are fun, too. If your picture wasn't broken, I'd be able to take a better look. Yay for MSPaint! Basically, a diode which a zener is a type oftakes a certain voltage to activate. You can put a dide in there that takes 7V to "turn on", or overcome the threshold. That way you have 5V supplied to the load.
Good job Hawkear, thats exactly what I was saying, except those zeners go the other way. In which case, what I would suggest to protect the 5V load from overload would be to put a zener in parallen with teh 5V load, so that if for some reason the 5V load is accidentally hooked up to the 12V rail, the zener will break down and short out to ground, protecting the 5V load.
In the circuit as configured you will have whatever the source voltage is present at all times going to the 12v device. When the source is above 5v you will have 5 volts to the 5v device limited by the current passed by the resistor.
What exactly are you trying to do? Anybody else thinking that you should just use an old PC PSU, and save the brainpower of building circuitry yourself? It's easy to bridge an ATX-connector to make it switch on Best Regards Bo Eriksson. I am awesome! So, something like this would be better, eh? Pretty much. If you can though, make the parallel zener 5.The plan is to burn the sketch to an Attiny micro controller mounted on a board along with the relay, transistors ect.
I currently have a working model on the bread board with the led's using the Any suggestions on how to get rid of the 9v battery weight reduction is the goaland use only the lipo battery to power everything?
You probably want to use a DC-to-DC converter or "buck" switching regulator. These are a very efficient way to reduce a higher voltage to a well-regulated lower voltage.
Update: I made this comment before seeing Peter's own comment 10 minutes earlier. Well, this way Peter doesn't have to try to track down the comment he made last April. Buck converters are great because they are the most stable. In the case of LiPO, the potential varies greatly over the discharge curve.
How to Reduce Voltage on 12 Volt System to 4 Volt
You say that you are currently using a 9 volt battery to power the Microcontroller. This implies to me that you already have a 5 volt regulator working in the circuit. I suspect that you can put the After reading andrews post about voltage regulators, other than price, is there an advantage to using this.
The LM is a single chip whereas R is an entire module. The module has a step-down regulator chip of some sort inside it, plus the additional discrete components the chip needs such as capacitors, resistors, diodes, transistors, and inductors.
In practice, designing the layout of a switching regulator module is tricky. Many step-down regulator chips run at very high frequencies -- 1 MHz or more -- and if you don't know what you're doing with the layout it could oscillate and produce an unstable output.
For example, if you put critical components too far from the chip the extra inductance of the PC board traces affect circuit function. I'm a digital guy so I prefer to leave the analog magic to analog experts. A module lets you do this.Forums New posts Search forums. Articles Top Articles Search resources. Members Current visitors. Log in Register. Search titles only. Search Advanced search…. New posts. Search forums. Log in. Welcome to our site! Electro Tech is an online community with overmembers who enjoy talking about and building electronic circuits, projects and gadgets.
Sorry i am quite new at this. Thanks in advance. You need a voltage regulator IC. The minimum voltage drop is about 2. You can use a regulator, but I suggest that you have a look at some LDO regulators Low Drop Outthat guarantee a better regulation if the input voltage is close to the output voltage typically 0.
Tarsil New Member. Last edited: Sep 20, A couple of things assume you are talking about DC voltage : A. Is the 12 volt source exactly that or more like While the difference may not seem like much, an extra volt helps with what eng1 mentions.
If you could stick with a or LM it will be easier to find one. What are the current requirements? Is this a preamp for RF or some kind of audio amp with significant power output.Menu Menu. Search Everywhere Threads This forum This thread. Search titles only.
Voltage Divider Calculator
TerryMathews Lifer. Oct 9, 11, 2 0. I'm going from 12V cigarette lighter power to 1. Original application was AAA battery, so I don't need to limit current. I need a way to step it down using as few components and as few wires as possible.
Ideally a discrete component with an in and an out, but I know that's not too likely. FrankSchwab Senior member. Nov 8, 0 0. How much current do you need? Assuming that it's fairly low, you might want to try an LM It's a three-terminal device with a maximum input voltage around 30 V, and a minimum output voltage of 1. You can certainly buy one at Radio Shack. The datasheet shows a typical hookup diagram.I have a power supply with output of 24V, 1A.
I need to reduce the voltage to 12V to power a water pump and to 5V in order to power an Arduino and an air pump. Can I just create a voltage divider using resistors for this? The water pump has an input of 12V, 5W.
Simple linear converters 78xx are unlikely to provide relief as they'll likely overheat. Switching converters are your best bet. Skip the voltage dividers. Answer 2 years ago.
That is, a load connected to the output of a voltage divider needs to have very high impedance to ameliorate the affect, and high impedance means low current from a fixed source voltage. Voltage dividers are not usable for power applications like this. Because if you connect any load resistance, then that load resistance is in parallel with one of the resistors in the divider, and the voltage sags.
Also lots of power is wasted as current goes positive to ground directly and is waste. Instead you want voltage regulators. Amazon has a lot of buck converters that are cheap and adequate for your application. Note that though the logic on Arduino is 5v, most boards prefer to have 9V or even more as their power supply. DON'T use a voltage divider - you will have an output that varies with load and if you are running a pump, it will be bad for it.
Your logic circuits won't like "5V" that varieseither. Follow Asked by DavidC in Circuits. Tags: arduino voltage pump power supply 24v 12v voltage divider resistor. Reply Upvote. Also lots of power is wasted as current goes positive to ground directly and is waste Instead you want voltage regulators. MichaelJ 2 years ago. If you want efficiency, get some buck switching regulators on Ebay.